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Generate YAML File from Directory Structure

Usage

generate_yaml_from_directory(
  input_path,
  output_yaml_path = "_project_structure_en.yaml",
  remove_prefix_numbers = FALSE
)

Arguments

input_path

String. The path to the directory whose structure needs to be captured.

output_yaml_path

String. The path where the YAML file will be saved.

remove_prefix_numbers

Boolean. Whether to remove numeric prefixes and any resulting leading non-alphanumeric characters from folder names. Defaults to FALSE.

Value

No return value, called for side effects

Examples

generate_yaml_from_directory(input_path=tempdir(),
   output_yaml_path = tempfile("_project_structure_en", fileext=".yaml"))